Purpose:
Shows the thermodynamic stability of metal oxides.
Helps predict the feasibility of the reduction of metal oxides to pure metals.
Axes:
X-axis: Temperature (K)
Y-axis: Standard Gibbs Free Energy change (ΔG°) in kJ/mol of O₂.
Lines:
Each line represents the reaction:
Metal + O₂ → Metal Oxide
(e.g., 2M + O₂ → 2MO)
The slope indicates entropy change; a steeper slope means higher ΔS.
Interpretation:
Lower line = more stable oxide.
A metal can reduce another metal's oxide if its line lies below that metal's oxide line.
Change in Slope:
Sharp changes in slope indicate phase changes (e.g., melting/boiling).
Identified by M (melting) and B (boiling).
Carbon and CO/CO₂ lines:
The red line represents the reaction:
C + O₂ → CO₂ and 2C + O₂ → 2CO.
Shows the conditions under which carbon can reduce metal oxides.
Hydrogen lines (grey):
Reactions involving H₂/H₂O show hydrogen-based reductions.
Less reducing than carbon at high temps.
Useful in Metallurgy:
Used to select a suitable reducing agent for extracting metals from ores.
Example:
Aluminum lies low on the diagram → Al₂O₃ is very stable → Al can reduce many metal oxides.
Limitations:
Only shows thermodynamics, not kinetics (reaction speed).
Also, it does not provide complete information about the oxides and their formations. Say, for example, more than one oxide is possible. The diagram gives us no representation of this scenario.
Q. Which one is thermodynamically feasible:
(a)Reduction of Cr2O3 by Al or
( b) reduction ofAl2O3 by Cr.
At a certain temperature, say at 1773 K (Diagram),
2Al + 3/2 O2 = Al2O3 ; ΔG = -900 KJ/mol
2Cr + 3/2 O2 = Cr2O3 ; ΔG= -500 KJ/mol
Al2O3 + Cr = Cr2O3 + Al ; ΔG = -500 - (-900) = 400 KJ/mol (+ve, not feasible)
Cr2O3 + Al = Al2O3 + Cr ; ΔG= -900- (-500) = -400 KJ/mol (-ve, feasible, spontaneous)